How do you factor $x^{3} - 6 x^{2} - x + 30$ $x^3-6x^2-x+30$ ?

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Answer 1 · 2015-09-27T02:15:28

Refer to explanation

We check using Rational Root theorem if any of the divisors of 30 are roots of the equation.

In our case $- 2, 3, 5$ $-2,3,5$ are roots of the equation hence the polynomial is factored as

$x^{3} - 6 x^{2} - x + 30 = (x + 2) (x - 3) (x - 5)$ $x^3-6x^2-x+30=(x+2)(x-3)(x-5)$

How do you factor x3−6x2−x+30x^3-6x^2-x+30?