How do you factor $x^3 - 9x^2 +27x - 27$ ?

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Answer 1 · 2018-07-02T16:36:59

$(x-3)^3$

$x^3-9x^2+27x-27$

= $x^3-27-9x^2+27x$

= $(x-3)(x^2+3x+9)-9x(x-3)$

= $(x-3)*(x^2+3x+9-9x)$

= $(x-3)*(x^2-6x+9)$

= $(x-3)*(x-3)^2$

= $(x-3)^3$

How do you factor x^3 - 9x^2 +27x - 27x^3 - 9x^2 +27x - 27?