How do you factor $x^3+9x^2+6x-56$ ?

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Answer 1 · 2015-05-27T04:49:13

Since f(2) = 0, then one factor is (x - 2)

$f(x) = (x - 2)( x^2 + 11x + 28)$

Factor (x^2 + 11x + 28) = (x - p)(x - q). Compose factor pairs of (28) --> (1, 28)(2, 14) (4, 7). This sum is 11 = b. Then p = 4 and q- 7.

f(x) = (x - 2)(x + 4)(x + 7)

How do you factor x^3+9x^2+6x-56x^3+9x^2+6x-56?