How do you factor $x^3+x^2-5x+3$ ?

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Answer 1 · 2015-05-30T12:56:52

First notice that $x=1$ is a solution of $x^3+x^2-5x+3=0$

So $(x-1)$ is a factor.

Let's use synthetic division to find.

$x^3+x^2-5x+3=(x-1)(x^2+2x-3)$

Notice that $x=1$ is a root of $x^2+2x-3=0$

So there's another factor $(x-1)$

$x^3+x^2-5x+3 = (x-1)(x-1)(x+3)$

How do you factor x^3+x^2-5x+3x^3+x^2-5x+3?