How do you factor $x (3 x - y z) + 2 y z (3 x - y z)$ $x(3x - yz) + 2yz(3x - yz)$ ?

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How do you factor $x (3 x - y z) + 2 y z (3 x - y z)$ $x(3x - yz) + 2yz(3x - yz)$ ?

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Answer 1 · 2016-02-13T14:03:35

(3x - yz)(x + 2yz )

Explanation:

in the expression $x (3 x - y z) + 2 y z (3 x - y z)$ $x(3x - yz ) + 2yz(3x - yz )$

there is a 'common factor' of (3x - yz )

removing this leaves x in the 1st term and +2yz in the 2nd.

hence factors are : (3x - yz )(x + 2yz )

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How do you factor $x (3 x - y z) + 2 y z (3 x - y z)$ $x(3x - yz) + 2yz(3x - yz)$ ?

1 Answer

Explanation:

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How do you factor $x (3 x - y z) + 2 y z (3 x - y z)$ $x(3x - yz) + 2yz(3x - yz)$ ?