How do you factor x^4 - 3x^2 - 4x43x24?

1 Answer
Apr 5, 2018

See a solution process below:

Explanation:

Because the x^4x4 coefficient is 11 we know the coefficient for the x^2x2 terms in the factor will also be 11:

(x^2 )(x^2 )(x2)(x2)

Because the constant is a negative and the coefficient for the xx term is a negative we know the sign for the constants in the factors will have one positive and one negative:

(x^2 + )(x^2 - )(x2+)(x2)

Now we need to determine the factors which multiply to -4 and also add to -3:

1 xx -4 = -41×4=4; 1 - 4 = -314=3 <- this IS the factor

(x^2 + 1)(x^2 - 4)(x2+1)(x24)

The factor (x^2 - 4)(x24) is a special form of the quadratic:

color(red)(x)^2 - color(blue)(y)^2 = (color(red)(x) + color(blue)(y))(color(red)(x) - color(blue)(y))x2y2=(x+y)(xy)

We can factor this term as:

(x^2 + 1)(color(red)(x) + color(blue)(2))(color(red)(x) - color(blue)(2))(x2+1)(x+2)(x2)