How do you factor $x^{4} + 7 x^{3} + 12 x^{2}$ $x^4+7x^3+12x^2$ ?

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How do you factor $x^{4} + 7 x^{3} + 12 x^{2}$ $x^4+7x^3+12x^2$ ?

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Answer 1 · 2015-10-28T10:37:05

$x^{2} (x + 3) (x + 4)$ $x^2 (x + 3)(x + 4)$

Explanation:

Well firstly;(remove $x^{2}$ $x^2$ )

$x^{2} (x^{2} + 7 x + 12)$ $x^2(x^2 +7x + 12)$
step 2; split the middle term
Sum = 7
product = 12
Possible factors;
$(4, 3)$ $(4,3)$

$x^{2} [(x^{2} + 4 x + 3 x + 12)]$ $x^2[ (x^2 +4x + 3x + 12)]$
$x^{2} [x (x + 4) + 3 (x + 4)]$ $x^2[ x(x + 4) + 3(x + 4)]$
$x^{2} (x + 3) (x + 4)$ $x^2 (x + 3)(x + 4)$

Tadaaa!! all done

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How do you factor $x^{4} + 7 x^{3} + 12 x^{2}$ $x^4+7x^3+12x^2$ ?

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How do you factor $x^{4} + 7 x^{3} + 12 x^{2}$ $x^4+7x^3+12x^2$ ?