How do you factor $x^{5} + 2 x^{4} - 3 x^{3}$ $x^5 + 2x^4 - 3x^3$ ?

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How do you factor $x^{5} + 2 x^{4} - 3 x^{3}$ $x^5 + 2x^4 - 3x^3$ ?

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Answer 1 · 2016-03-23T19:43:40

$x^{3} (x + 3) (x - 1)$ $x^3(x+3)(x-1)$

Explanation:

To factor $x^{5} + 2 x^{4} - 3 x^{3}$ $x^5 + 2x^4 - 3x^3$ completely begin by factoring out the common factor $x^{3}$ $x^3$

$x^{3} (x^{2} + 2 x - 3)$ $x^3(x^2+2x-3)$
now factor the trinomial using
$(3) (- 1) = - 3$ $(3)(-1) = -3$
$3 - 1 = 2$ $3-1 = 2$
$(x + 3) (x - 1)$ $(x+3)(x-1)$

$x^{3} (x + 3) (x - 1)$ $x^3(x+3)(x-1)$

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How do you factor $x^{5} + 2 x^{4} - 3 x^{3}$ $x^5 + 2x^4 - 3x^3$ ?

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