How do you factor x6x412x2?

1 Answer
May 25, 2015

Given x6x412x2

Step 1: extract the obvious common factor x2
=(x2)(x4x212)

Step 2: simplify the second term by temporarily substituting t=x2
=(x2)(t2t12)
=(x2)(t4)(t+3)

Step 3: re-insert x2 in place of t
=(x2)(x24)(x2+3)

Step 4: factor the middle term as the difference of squares
=(x2)(x+2)(x2)(x2+3)