How do you factor $x²+9x+18$ ?

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Answer 1 · 2018-03-24T11:01:27

$(x+3)(x+6)$

$"using the a-c method to factor the quadratic"$

$"the factors of + 18 which sum to + 9 are + 3 and + 6"$

. $rArrx^2+9x+18=(x+3)(x+6)$

How do you factor x²+9x+18x²+9x+18?