How do you factor $x - d + {(x - d)}^{2}$ $x - d + (x - d)^2$ ?

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Answer 1 · 2016-08-10T13:43:14

$= (x - d) (1 + x - d)$ $=(x-d)(1+x-d)$

$x - d + {(x - d)}^{2}$ $x-d+(x-d)^2$
$= (x - d) (1 + x - d)$ $=(x-d)(1+x-d)$

Answer 2 · 2016-08-10T15:45:11

$(x - d) (1 + x - d)$ $(x-d)(1+x-d)$

Before we try to factorise, let's make 2 small changes:
There are 3 terms, but group the first two so that we have 2 terms.

$(x - d) + (x - d) (x - d) there is a common bracket$ $color(red)((x-d)) + color(red)((x-d))(x-d) " there is a common bracket"$

$(x - d) (1 + x - d)$ $color(red)((x-d))(1+x-d)$

There are two factors.

How do you factor x−d+(x−d)2x - d + (x - d)^2?