How do you factor $y^{2} + 2 x y - 63 x^{2}$ $y^2+2xy - 63x^2$ ?

Question

How do you factor $y^{2} + 2 x y - 63 x^{2}$ $y^2+2xy - 63x^2$ ?

1 Answer

Impact of this question

1699 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-22T23:45:59

Notice that $63 = 9 \times 7$ $63 = 9 xx 7$ and $2 = 9 - 7$ $2 = 9 - 7$ , so

$y^{2} + 2 x y - 63 x^{2} = (y - 7 x) (y + 9 x)$ $y^2+2xy-63x^2 = (y-7x)(y+9x)$

When the coefficient of the first term in one of these quadratics is $1$ $1$ , look for factors of the coefficient of the last term, whose sum or difference is the middle coefficient.

Science

Math

Humanities

... and beyond

How do you factor $y^{2} + 2 x y - 63 x^{2}$ $y^2+2xy - 63x^2$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor y2+2xy−63x2y^2+2xy - 63x^2 ?

1 Answer

Related questions

Impact of this question

How do you factor $y^{2} + 2 x y - 63 x^{2}$ $y^2+2xy - 63x^2$ ?