How do you factor $y^{2} + 3 y - 18$ $y^2 +3y-18$ ?

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Answer 1 · 2015-06-14T05:02:15

Factor: f(y) = y^2 + 3y - 18

Find 2 numbers, sum = 3 and product = -18. Factor pairs of (-18)--> (-2, 9)(-3, 6). OK. This sum is 3 = b.

f(y) = (y - 3)(y + 6).

How do you factor y2+3y−18y^2 +3y-18 ?