How do you find 2p(a) + p(a - 1) if $p(x) = x^2 + x$ ?

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Answer 1 · 2016-07-19T18:23:47

$2p(a)+p(a-1)=3a^2+a$ .

Given poly. $p(x)=x^2+x$

To find $p(a)$ , we have to just put $a$ , in place of $x$ ,

Hence, $p(a)=a^2+a$ , and, $p(a-1)=(a-1)^2+(a-1)=(a-1)(a-1+1)=a(a-1)$ .

Therefore, $2p(a)+p(a-1)=2(a^2+a)+a(a-1)=2a^2+2a+a^2-a=3a^2+a$ .

How do you find 2p(a) + p(a - 1) if p(x) = x^2 + xp(x) = x^2 + x?