Question

How do you find all solutions to `(sin x)(cos x) = 0` on [0,2pi)?

Answer 1

`x=pi or x=pi/2,(3pi)/2`

Explanation:

`sinx=0 or cosx=0`
`x=sin^-1 0 or x=cos^-1 0`
`x=pi or x=pi/2,(3pi)/2`