How do you find all the zeros of $f (x) = x^{2} - 8 x + 12$ $f(x) = x^2 - 8x + 12$ ?

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How do you find all the zeros of $f (x) = x^{2} - 8 x + 12$ $f(x) = x^2 - 8x + 12$ ?

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Answer 1 · 2016-04-05T18:00:44

x = 2 , x = 6

Explanation:

Zeros are the values of x that make the function equal zero.

ie $x^{2} - 8 x + 12 = 0$ $x^2 - 8x + 12 = 0$

Factor the quadratic and solve for x.

$\Rightarrow x^{2} - 8 x + 12 = (x - 2) (x - 6) = 0$ $rArr x^2 - 8x + 12 = (x - 2 )(x - 6 ) = 0$

x - 2 = 0 → x = 2

x - 6 = 0 → x = 6

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How do you find all the zeros of $f (x) = x^{2} - 8 x + 12$ $f(x) = x^2 - 8x + 12$ ?

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Explanation:

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How do you find all the zeros of $f (x) = x^{2} - 8 x + 12$ $f(x) = x^2 - 8x + 12$ ?