How do you find all the zeros of #x^2 + 24 = 11x#?

Question

1453 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-19T14:01:22

#=>x^2-11x+24=0#
#=>x^2-8x-3x+24=0#
#=>x(x-8)-3(x-8)=0#
#=>(x-8)(x-3)=0#
#: . x= 3and x= 8# are the two values for zero