How do you find all the zeros of $x^2 + 24 = 11x$ ?

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Answer 1 · 2016-04-19T14:01:22

$=>x^2-11x+24=0$
$=>x^2-8x-3x+24=0$
$=>x(x-8)-3(x-8)=0$
$=>(x-8)(x-3)=0$
$: . x= 3and x= 8$ are the two values for zero

How do you find all the zeros of x^2 + 24 = 11xx^2 + 24 = 11x?