How do you find all the zeros of $x^{4} - x^{3} - 20 x^{2}$ $x^4-x^3-20x^2$ ?

Question

2822 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-07T15:53:21

You must set the expression to 0 and factor.

$x^{2} (x^{2} - x - 20) = 0$ $x^2(x^2 - x - 20) = 0$

$x^{2} (x - 5) (x + 4) = 0$ $x^2(x - 5)(x + 4) = 0$

$x = 0, 5, - 4$ $x = 0, 5, -4$

Hopefully this helps!

How do you find all the zeros of x^4-x^3-20x^2x4−x3−20x2 x^4-x^3-20x^2?