How do you find all zeros for x^3 - 5x^2 + x - 5? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Alan P. May 17, 2016 x =5 or x=+-i Explanation: x^3-5x^2+x-5 can be factored as color(white)("XXX")color(red)(""(x^3+x))-color(blue)(""(5x^2+5)) color(white)("XXX")=color(red)(x(x^2+1))-color(blue)(5(x^2+1) color(white)("XXX")=(color(red)(x)-color(blue)(5))*(x^2+1) For the zeroes: either color(white)("XXX")(x-5)=0color(white)("XX")rarrcolor(white)("XX")x=5 or color(white)("XXX")(x^2+1)=0color(white)("XX")rarrcolor(white)("XX")x=+-sqrt(-1)=+-i Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of f(x) = 5x^7 − x + 216? What are the zeros of f(x)= −4x^5 + 3? How many times does f(x)= 6x^11 - 3x^5 + 2 intersect the x-axis? What are the real zeros of f(x) = 3x^6 + 1? How do you find the roots for 4x^4-26x^3+50x^2-52x+84=0? What are the intercepts for the graphs of the equation y=(x^2-49)/(7x^4)? See all questions in Zeros Impact of this question 4529 views around the world You can reuse this answer Creative Commons License