How do you find all zeros of $f(x)=1/3x^2+1/3x-2/3$ ?

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Answer 1 · 2017-06-01T16:55:04

Zeros of $f(x)$ are $x=1$ and $x=-2$ .

$f(x)=1/3x^2+1/3x-2/3=1/3(x^2+x-2)$

= $1/3(x^2+2x-x-2)$

= $1/3(x(x+2)-1(x+2))$

= $1/3(x-1)(x+2)$

Hence, zeros of $f(x)$ are $x=1$ and $x=-2$ .

How do you find all zeros of f(x)=1/3x^2+1/3x-2/3f(x)=1/3x^2+1/3x-2/3?