How do you find all zeros of the function f(x)=10x^2+5x-5?
1 Answer
Aug 5, 2016
Explanation:
f(x) = 10x^2+5x-5=5(2x^2+x-1)=5(2x-1)(x+1)
Hence
f(x) = 10x^2+5x-5=5(2x^2+x-1)=5(2x-1)(x+1)
Hence