How do you find all zeros of the function $f (x) = x^{2} - 4 x - 60$ $f(x) = x^2 - 4x - 60$ ?

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Answer 1 · 2016-03-13T21:26:56

The x-axis intercepts are at $x = 10 and x = - 6$ $x= 10" and "x=-6$

$6 \times 10 = 60$ $6xx10=60$
$6 - 10 = - 4$ $6-10=-4$

$(x - 10) (x + 6)$ $(x-10)(x+6)$

$x = 10 and x = - 6$ $x= 10" and "x=-6$

How do you find all zeros of the function f(x) = x^2 - 4x - 60f(x)=x2−4x−60f(x) = x^2 - 4x - 60?