How do you find cot x if sin x cot x csc x = √2?

1 Answer
Jan 4, 2016

cot x = √2cotx=2

Explanation:

note that the function # cscx = 1/sinx

hence sinx xx cotx xx 1/sinx =sqrt 2sinx×cotx×1sinx=2

cancelling out the sinxsinx terms

gives cotx = sqrt2cotx=2