How do you find $csc x = - \sqrt 2$ $csc x = -√2$ ?

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Answer 1 · 2015-07-02T04:19:27

Find $csc x = - \sqrt{2}$ $csc x = -sqrt2$

$csc x = \frac{1}{sin x} = - \sqrt{2}$ $csc x = 1/sin x = -sqrt2$

On the trig unit circle,

$sin x = - \frac{1}{\sqrt{2}} = - \frac{\sqrt{2}}{2}$ $sin x = - 1/(sqrt2) = - (sqrt2)/2$ --> $x = - \frac{π}{4}$ $x = - pi/4$ or - 45 deg

and $x = - \frac{3 π}{4}$ $x = - (3pi)/4$ or - 135 deg

How do you find csc x = -√2cscx=−√2csc x = -√2?