How do you find dy/dx by implicit differentiation for $2 x^{3} + x^{2} \cdot y - x y^{3} = 6$ $2x^3 + x^2*y - xy^3 = 6$ ?

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How do you find dy/dx by implicit differentiation for $2 x^{3} + x^{2} \cdot y - x y^{3} = 6$ $2x^3 + x^2*y - xy^3 = 6$ ?

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Answer 1 · 2015-04-10T03:48:13

You must remember that $y$ $y$ is a function of $x$ $x$ and derive it as well:
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I used the Product Rule for $x^{2} y$ $x^2y$ and $x y^{3}$ $xy^3$ .

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How do you find dy/dx by implicit differentiation for $2 x^{3} + x^{2} \cdot y - x y^{3} = 6$ $2x^3 + x^2*y - xy^3 = 6$ ?

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How do you find dy/dx by implicit differentiation for 2x^3 + x^2*y - xy^3 = 62x3+x2⋅y−xy3=62x^3 + x^2*y - xy^3 = 6?

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How do you find dy/dx by implicit differentiation for $2 x^{3} + x^{2} \cdot y - x y^{3} = 6$ $2x^3 + x^2*y - xy^3 = 6$ ?