How do you find #dy/dx# by implicit differentiation given #x^3=y^5#?
1 Answer
Dec 11, 2016
Explanation:
differentiate
#color(blue)"implicitly with respect to x"# differentiate both sides using the
#color(blue)"power rule"#
#rArr3x^2=5y^4.dy/dx#
#rArrdy/dx=(3x^2)/(5y^4)#