How do you find dy/dxdydx by implicit differentiation of x^3+y^3=8x3+y3=8?
1 Answer
Feb 13, 2017
Explanation:
We have:
x^3+y^3=8 x3+y3=8
Differentiate wrt
3x^2 + d/dxy^3=0 3x2+ddxy3=0
:. 3x^2 + dy/dxd/dyy^3=0
:. 3x^2 + dy/dx(3y^2)=0
:. x^2 + y^2dy/dx=0
:. dy/dx=-x^2/y^2