Question

How do you find f'(1) if `f(x)= x^2*tan^-1 x`?

Answer 1

It would be `pi/2+1/2`

f' (x)= `2x tan^-1 x + x^2 /(1+x^2)`

f' (1)= `2tan^-1 1+ 1/2`

=`2pi/4 +1/2`

=`pi/2 +1/2`