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How do you find f'(4) using the limit definition given $f(x) = x+3$ ?

1 Answer

Sep 18, 2017

see below

Explanation:

$f'(x)=Lim_(hrarr0)(f(x+h)-f(x))/h$

in this case

$f(x)=x+3$

applying the definition

$f'(x)=Lim_(hrarr0)(cancel(x+3)+h-cancel((x+3)))/h$

$f'(x)=Lim_(hrarr0)h/h=Lim_(hrarr0)1=1$

$f'(x)=1:.f'(4)=1$

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