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How do you find f'(x) using the definition of a derivative for $f (x) = 7 x^{2} - 3$ $f(x)=7x^2 - 3$ ?

1 Answer

Oct 26, 2015

$f'(x)=14x$

Explanation:

The rules:
The derivative of a number is $0$
The derivative of a power of $x$ is power times $x$ to power-1.

So if $g(x)=x^2->g'(x)=2*x^(2-1)=2x$

So here we get:
$f'(x)=7*2x-0=14x$

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