How do you find f'(x) using the definition of a derivative for $f (x) = - 7 x^{2} + 4 x$ $f(x)= -7x^2 + 4x$ ?

Question

How do you find f'(x) using the definition of a derivative for $f (x) = - 7 x^{2} + 4 x$ $f(x)= -7x^2 + 4x$ ?

1 Answer

Related questions

What is the limit definition of the derivative of the function $y=f(x)$ ?
Ho do I use the limit definition of derivative to find $f'(x)$ for $f(x)=3x^2+x$ ?
How do I use the limit definition of derivative to find $f'(x)$ for $f(x)=sqrt(x+3)$ ?
How do I use the limit definition of derivative to find $f'(x)$ for $f(x)=1/(1-x)$ ?
How do I use the limit definition of derivative to find $f'(x)$ for $f(x)=x^3-2$ ?
How do I use the limit definition of derivative to find $f'(x)$ for $f(x)=1/sqrt(x)$ ?
How do I use the limit definition of derivative to find $f'(x)$ for $f(x)=5x-9x^2$ ?
How do I use the limit definition of derivative to find $f'(x)$ for $f(x)=sqrt(2+6x)$ ?
How do I use the limit definition of derivative to find $f'(x)$ for $f(x)=mx+b$ ?
How do I use the limit definition of derivative to find $f'(x)$ for $f(x)=c$ ?

Impact of this question

1635 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-27T18:38:09

See explanation

Explanation:

It is

$f'(x)=lim_(h->0) ((f(x+h)-f(x))/h) => f'(x)=lim_(h->0)(-7*(x+h)^2+4(x+h)-(-7x^2+4x))/h=> f'(x)=lim_(h->0) ((-h(7h+2*(7x-2)))/h)=> f'(x)=lim_(h->0) (-(7h+2(7x-2)))=> f'(x)=-14x+4$

Science

Math

Humanities

... and beyond

How do you find f'(x) using the definition of a derivative for $f (x) = - 7 x^{2} + 4 x$ $f(x)= -7x^2 + 4x$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find f'(x) using the definition of a derivative for f(x)= -7x^2 + 4x f(x)=−7x2+4xf(x)= -7x^2 + 4x ?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find f'(x) using the definition of a derivative for $f (x) = - 7 x^{2} + 4 x$ $f(x)= -7x^2 + 4x$ ?