How do you find $int (x+6)/(x+10)$ ?

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Answer 1 · 2015-11-01T22:24:40

$(x+6)/(x+10) = ((x+10)-4)/(x+10) = 1-4/(x+10)$

Now integrate.

Use substitution for the second integral:

$-4int 1/(x+10) dx = -4ln abs(x+10)+C$

How do you find int (x+6)/(x+10) int (x+6)/(x+10) ?