Question

How do you find real zero of a function `f(x) = x^2 + 5x +6`?

Answer 1

`x=-3,x=-2`

Explanation:

`"equate "f(x)" to zero"`

`rArrx^2+5x+6=0larrcolor(blue)"in standard form"`

`"the factors of + 6 which sum to + 5 are + 3 and + 2"`

`rArr(x+3)(x+2)=0`

`"equate each factor to zero and solve for x"`

`x+3=0rArrx=-3`

`x+2=0rArrx=-2`
graph{x^2+5x+6 [-10, 10, -5, 5]}