How do you find s[h(x)] if $s (x) = 2^{x}$ $s(x) = 2^x$ and $h (x) = x^{2}$ $h(x) = x^2$ ?

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Answer 1 · 2016-01-04T06:18:53

$s (h (x)) = 2^{x^{2}}$ $s(h(x))=2^(x^2)$

$s (h (x))$ $s(h(x))$ is a way of saying put $h (x)$ $h(x)$ in $s (x)$ $s(x)$ .

In other words, take $x^{2}$ $x^2$ , and plug it in the spot where $x$ $x$ is in $2^{x}$ $2^x$ .

$s (h (x)) = 2^{x^{2}}$ $s(h(x))=2^(x^2)$

How do you find s[h(x)] if s(x) = 2^xs(x)=2xs(x) = 2^x and h(x) = x^2h(x)=x2h(x) = x^2?