How do you find slope and intercepts to graph $4x+3y=-3$ ?

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Answer 1 · 2016-01-08T03:43:08

Slope $=(-4)/3$

Y-Intercept $=-1$

The given equation is in the form -

$ax+by=c$

To find its slope use the formula

$m=(-a)/b=(-4)/3$

To find its intercept , put $x=0$

At $x=0; 4(0)+3y =-3$

$3y=-3$
$y=(-3)/3=-1$

Slope $=(-4)/3$

Y-Intercept $=-1$

How do you find slope and intercepts to graph 4x+3y=-34x+3y=-3?