Question

How do you find the amplitude and period of `y=2sin.5x`?

Answer 1

Amplitude is `2` and period is `4pi`

Explanation:

The amplitude `A` is represented by the number in front of the `sin` function so:
`A=2`
The period is given as `(2pi)/k` where `k` is the number in front of `x` in the argument of `sin`:
so period`=(2pi)/0.5=4pi~~12.5` that represents the interval needed to complete one oscillation.
Graphically:
graph{2*sin(0.5x) [-16.02, 16.02, -8.01, 8.01]}