How do you find the antiderivative $f(x)=6/x^5$ ?

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Answer 1 · 2015-06-08T18:21:36

Note that $\int x^{n}\ dx=x^{n+1}/(n+1)+C$ when $n!=-1$ and that $\int af(x)\ dx=a\int f(x)\ dx$ for any constant $a$ .

Hence $\int 6/(x^5)\ dx=6\int x^{-5}\ dx=6* x^{-4}/(-4)+C=-3/(2x^4)+C$

How do you find the antiderivative f(x)=6/x^5f(x)=6/x^5?