Question

How do you find the axis of symmetry and vertex point of the function: `y=2x^2 + 1`?

Answer 1

The function is already in completed square form (explicitly `2(x-0)^2 + 1`), so we can see the axis of symmetry is `x=0` (which in fact is the y axis) and the vertex point is `(0,1)`.

Explanation:

graph{y=2x^2+1 [-9.45, 10.55, -1.08, 8.92]}