Question

How do you find the axis of symmetry and vertex point of the function: `y = 2x^2 – 12x + 22`?

Answer 1

Vertex of `y = 2x^2 - 12x + 22`

Ans: Vertex (3, 4)

Explanation:

x-coordinate of axis of symmetry and vertex:
`x = (-b/2a) = 12/4 = 3`
y-coordinate of vertex:
y = f(3) = 18 - 36 + 22 = 4
graph{2x^2 - 12x + 22 [-20, 20, -10, 10]}