How do you find the axis of symmetry and vertex point of the function: y = 2x^2 + 24x + 62y=2x2+24x+62?

1 Answer
bhaskar m.
Jun 9, 2018

The Axis of Symmetry occurs at x=-6x=−6
The Vertex occurs at (x,y)=(-6, -10)(x,y)=(−6,−10)

Explanation:

The axis of symmetry of a quadratic equation is always located at x=\frac{-b}{2a}x=−b2a which in this case is equal to \frac{-24}{2\cdot2}=-6−242⋅2=−6.

\therefore Axis of Symmetry occurs at x=-6

The vertex is the point that the function takes at the axis of symmetry.

\therefore in the case of this problem, the vertex is (-6,f(-6)) which is equal to (-6, -10)

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