Question

How do you find the axis of symmetry and vertex point of the function: `y = 2x^2 + 24x + 62`?

Answer 1

The Axis of Symmetry occurs at `x=-6`
The Vertex occurs at `(x,y)=(-6, -10)`

Explanation:

The axis of symmetry of a quadratic equation is always located at `x=\frac{-b}{2a}` which in this case is equal to `\frac{-24}{2\cdot2}=-6`.

`\therefore` Axis of Symmetry occurs at `x=-6`

The vertex is the point that the function takes at the axis of symmetry.

`\therefore` in the case of this problem, the vertex is `(-6,f(-6))` which is equal to `(-6, -10)`