How do you find the center and radius for (x + 14)^2 + (y - 6)^2 = 9(x+14)2+(y−6)2=9?
1 Answer
Aug 24, 2016
centre = (-14 ,6), radius = 3
Explanation:
The standard equation of a circle is.
color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))
where (a ,b) are the coordinates of the centre and r, the radius.The equation here is in this form and by comparison.
a=-14,b=6" and " r^2=9rArrr=3
rArr" centre " =(-14,6)" and " r=3
