How do you find the center and radius of $( x - 3 )^ 2 + y ^2 = 4$ ?

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Answer 1 · 2016-12-02T10:50:38

The center is $(3,0)$ and the radius $=2$

The equation of a circle is

$(x-a)^2+(y-b)^2=r^2$

The center is $(a,b)$ and the radius $r$

We compare this to your equation

$(x-3)^2+(y-0)^2=2^2$

So,

The center is $(3,0)$ and the radius $=2$

graph{(x-3)^2+(y)^2=4 [-6.24, 6.244, -3.12, 3.12]}

How do you find the center and radius of ( x - 3 )^ 2 + y ^2 = 4( x - 3 )^ 2 + y ^2 = 4?