How do you find the center and radius of $(x – 9)^2 + y^2 = 484$ ?

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Answer 1 · 2016-02-19T04:56:16

$(9, 0)$ is the center and $22$ is radius.

Equation of a circle with center at $()a, b)$ and radius $r$ can be expressed as

$(x-a)^2+(y-b)^2=r^2$ , as any point $(x,y)$ will be at a distance of $r$ from center at $(a,b)$ .

As the equation $(x–9)^2+y^2=484$ can be written as

$(x–9)^2+(y-o)^2=22^2$

It is obvious from the equation that

$(9, 0)$ is the center and $22$ is radius.

How do you find the center and radius of (x – 9)^2 + y^2 = 484 (x – 9)^2 + y^2 = 484?