Question

How do you find the complex roots of `n^3-9n=0`?

Answer 1

`"there are no complex roots"`

Explanation:

`n^3-9n=0`

`rArrn(n^2-9)=0`

`rArrn(n-3)(n+3)=0`

`"equating each factor to zero and solving for n"`

`rArrn=0`

`n-3=0rArrn=3`

`n+3=-rArrn=-3`

`"the roots "n=0,n=3,n=-3" are real"`