How do you find the complex roots of t^3+2t^2-4t-8=0?

1 Answer
Nov 26, 2016

The roots are:

-2, -2, 2

Explanation:

0 = t^3+2t^2-4t-8

color(white)(0) = (t^3+2t^2)-(4t+8)

color(white)(0) = t^2(t+2)-4(t+2)

color(white)(0) = (t^2-4)(t+2)

color(white)(0) = (t^2-2^2)(t+2)

color(white)(0) = (t-2)(t+2)(t+2)

So the roots are:

-2, -2, 2

There are no non-Real Complex roots.