How do you find the complex roots of t^3+2t^2-4t-8=0?
1 Answer
Nov 26, 2016
The roots are:
-2, -2, 2
Explanation:
0 = t^3+2t^2-4t-8
color(white)(0) = (t^3+2t^2)-(4t+8)
color(white)(0) = t^2(t+2)-4(t+2)
color(white)(0) = (t^2-4)(t+2)
color(white)(0) = (t^2-2^2)(t+2)
color(white)(0) = (t-2)(t+2)(t+2)
So the roots are:
-2, -2, 2
There are no non-Real Complex roots.