How do you find the coordinates of the midpoint of CM with endpoints C(1,-6) and M(7,5)?
1 Answer
Nov 28, 2016
(x, y)=(4, -0.5)(x,y)=(4,−0.5)
Explanation:
The co-ordinates of the mid-point of a line is given by -
(x, y)=(x_1+x_2)/2, (y_1+y_2)/2(x,y)=x1+x22,y1+y22
x_1=1x1=1
x_2=7x2=7
y_1=-6y1=−6
y_2=5y2=5
Then-
(x, y)=(1+7)/2, (-6+5)/2(x,y)=1+72,−6+52
(x, y)=(8)/2, (-1)/2(x,y)=82,−12
(x, y)=(4, -0.5)(x,y)=(4,−0.5)
