How do you find the critical numbers of $\frac{1}{t^{2} + 3}$ $1/(t^2+3)$ ?

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Answer 1 · 2017-12-08T16:23:58

The on;y critical number is $0$ $0$ .

$f (t) = \frac{1}{t^{2} + 3}$ $f(t) = 1/(t^2+3)$

$f'(t) = (-2t)/(t^2+3)^2$

$f'(t)$ is never undefined and is $0$ only at $t=0$

How do you find the critical numbers of 1/(t^2+3)1t2+31/(t^2+3)?