How do you find the critical points for $F (x) = x e^{- x}$ $F(x) =xe^-x$ ?

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Answer 1 · 2015-11-08T14:58:03

$f (x)$ $f(x)$ is differentiable everywhere, so the critical points will simply be the solution(s) to $f'(x)=0$

$f'(x)=e^-x(1-x)=0$

critical point at $1-x=0$ or $x=1$

hope that helped

How do you find the critical points for F(x) =xe^-xF(x)=xe−xF(x) =xe^-x?