How do you find the Critical Points for $x^3 + 3x^2-24x$ ?

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Answer 1 · 2015-09-11T05:29:50

Critical points are 2, -4

critical point 'c' of a function is where either f'(c)=0 or f'(c) does not exist.

To find critical point f'(x)= $3x^2 +6x -24=0$

That gives $x^2 +2x -8=0$

$(x+4)(x-2)=0$

Critical points are 2, -4

How do you find the Critical Points for x^3 + 3x^2-24xx^3 + 3x^2-24x?