Question

How do you find the critical points of `f'(x)=15-5x`?

Answer 1

Critical point at `x=3`.

Explanation:

Critical points occur at `c` if `f'(c) = 0` or `f'(c)` does not exist.

`f'(x)=0`

So

`15-5x = 0`

`15=5x`

`x=3`